Разложите на множители квадратный трехчлен: 1/3y^2-2/9y-1/9.

\[\frac{1}{3}y² - \frac{2}{9}y - \frac{1}{9} = 0\ \ \ \ \ \ \ | \cdot 9\]

\[3y² - 2y - 1 = 0\]

\[D_{1} = 1 + 3 = 4\]

\[y_{1} = \frac{1 + 2}{3} = 1;\ \ \ \]

\[y_{2} = \frac{1 - 2}{3} = - \frac{1}{3}.\]

\[\frac{1}{3}y^{2} - \frac{2}{9}y - \frac{1}{9} =\]

\[= \frac{1}{3} \cdot (y - 1)\left( y + \frac{1}{3} \right).\]