\[3\sqrt{5} = \sqrt{3^{2} \cdot 5} = \sqrt{9 \cdot 5} = \sqrt{45}\]
\[2\sqrt{8} = \sqrt{2^{2} \cdot 8} = \sqrt{4 \cdot 8} = \sqrt{32}\]
\[6 = \sqrt{6^{2}} = \sqrt{36}\]
\[\sqrt{32} < \sqrt{36} < \sqrt{45}\]
\[Числа\ в\ порядке\ возрастания:\]
\[2\sqrt{8} < 6 < 3\sqrt{5}\]