\[2\sqrt{12} = \sqrt{4 \cdot 12} = \sqrt{48}\]
\[5\sqrt{2} = \sqrt{25 \cdot 2} = \sqrt{50}\]
\[7 = \sqrt{49}\]
\[\sqrt{50} > \sqrt{49} > \sqrt{48}\]
\[Числа\ в\ порядке\ убывания:\]
\[5\sqrt{2} > 7 > 2\sqrt{12}.\]