\[y = kx + b;\ \ \ A( - 3;26);\ \ B(5; - 22).\]
\[Подставим\ координаты\ точек\ в\ \]
\[уравнение\ прямой\ и\ запишем\]
\[систему:\]
\[\left\{ \begin{matrix} - 3k + b = 26 \\ 5k + b = - 22 \\ \end{matrix} \right.\ ( - )\]
\[- 8k = 48\]
\[k = - 6.\]
\[\left\{ \begin{matrix} b = 26 + 3k \\ k = - 6\ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\left\{ \begin{matrix} k = - 6\ \ \ \ \ \ \ \ \ \ \\ b = 26 - 18 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]
\[\left\{ \begin{matrix} k = - 6 \\ b = 8\ \ \ \\ \end{matrix} \right.\ \]
\[Уравнение\ прямой:\]
\[y = - 6x + 8.\]