Приведите дробь: 3/(b-5) к знаменателю b^2 -5b.

Question

\[к\ знаменателю\ \]

\[b^{2} - 5b = b(b - 5);\]

\[\frac{3}{b - 5} = \frac{3b}{b(b - 5)} = \frac{3b}{b^{2} - 5b}\]

Accepted Answer

\[к\ знаменателю\ \]

\[b^{2} - 5b = b(b - 5);\]

\[\frac{3}{b - 5} = \frac{3b}{b(b - 5)} = \frac{3b}{b^{2} - 5b}\]

Ответ: