\[\sqrt{x\left( \sqrt{2} - \sqrt{3} \right)} + \sqrt{x + 3};\]
\[\left\{ \begin{matrix} x\left( \sqrt{2} - \sqrt{3} \right) \geq 0 \\ x + 3 \geq 0\ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]
\[\sqrt{2} - \sqrt{3} < 0;так\ как\]
\[\sqrt{2} < \sqrt{3}.\]
\[\left\{ \begin{matrix} x \leq 0\ \ \ \ \\ x \geq - 3 \\ \end{matrix} \right.\ \]
\[- 3 \leq x \leq 0.\]
\[Ответ:\ - 3 \leq x \leq 0.\]