\[px^{2} + (2p - 3)x + (p + 3) > 0\]
\[При\ p > 0;\ \ D < 0:\]
\[D = (2p - 3)^{2} - 4p(p + 3) =\]
\[= 4p^{2} - 12p + 9 - 4p^{2} - 12p =\]
\[= - 24p + 9;\]
\[- 24p + 9 < 0\]
\[24p > 9\]
\[p > \frac{3}{8}.\]
\[Ответ:при\ p > \frac{3}{8}.\]