\[\frac{(b - 2)^{2} + 8b + 1}{b} =\]
\[= \frac{b^{2} - 4b + 4 + 8b + 1}{b} =\]
\[= \frac{b^{2} + 4b + 5}{b} = b + 4 + \frac{5}{b};\]
\[При\ b = \pm 1;b = \pm 5.\]