\[\frac{2}{x + 3} + \frac{18x}{x^{3} + 27} - \frac{x + 3}{x^{2} - 3x + 9} =\]
\[= \frac{x^{2} + 6x + 9}{(x + 3)\left( x^{2} - 3x + 9 \right)} =\]
\[= \frac{x + 3}{x^{2} - 3x + 9} = \frac{x + 3}{x^{2} - 3x + 9} =\]
\[= \frac{- 3 + 3}{( - 3)^{2} - 3 \cdot ( - 3) + 9} = 0\]