\[S_{кр} = \pi R^{2}\]
\[\frac{S_{м.кр.}\text{\ \ \ }}{S_{б.кр.}} = \frac{\pi \cdot 4^{2}}{\pi \cdot R^{2}} = \frac{1}{16}\]
\[\frac{16}{R^{2}} = \frac{1}{16}\]
\[R^{2} = 256\ \ см\]
\[R = 16\ см.\]
\[Ответ:\ \ 16\ см - радиус\ \]
\(большего\ круга.\)