\[\frac{1}{9} = \frac{1}{3^{2}} = \left( \frac{1}{3} \right)^{2} = \left( - \frac{1}{3} \right)^{2};\]
\[\frac{1}{81} = \frac{1}{3^{4}} = \left( \frac{1}{3} \right)^{4} = \left( - \frac{1}{3} \right)^{4}.\]