\[\frac{y - 1}{x + 1} = \frac{3 + 2x}{x + 1}\]
\[y - 1 - 3 + 2x = 0;\ \ \ \ x eq - 1\]
\[y - 4 + 2x = 0\]
\[y = 4 - 2x;\ \ \ x eq - 1\]