Постройте график функции: y=x/|x|(1/5x^2-2x+2).

Ответ:

\[y = \frac{x}{|x|}\left( \frac{1}{5}x^{2} - 2x + 2 \right)\]

\[\left\{ \begin{matrix} x > 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ y = \frac{1}{5}x^{2} - 2x + 2 \\ \end{matrix}\text{\ \ \ \ \ } \right.\ \text{\ \ \ \ }\]

\[\left\{ \begin{matrix} x < 0\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ y = - \frac{1}{5}x² + 2x - 2 \\ \end{matrix} \right.\ \]