Постройте график функции: y=x^2+4x+3.

Question

Вопрос:

Ответ:

Accepted Answer

\[y = x² + 4x + 3 \Longrightarrow ветви\ вверх\]

\[x_{0} = \frac{- 4}{2} = - 2;\ \ \]

\[y_{0} = 4 - 8 + 3 = - 1\]

\[( - 2;\ - 1).\]

\[x\]	\[0\]	\[- 3\]
\[y\]	\[3\]	\[0\]