Постройте график функции: y=-x^2+4x-3.

Question

\[y = - x^{2} + 4x - 3\]

\[x_{0} = \frac{- 4}{- 2} = 2;\ \ y_{0} = 1\]

\[x\]	\[0\]	\[1\]
\[y\]	\[- 3\]	\[0\]

Accepted Answer

\[y = - x^{2} + 4x - 3\]

\[x_{0} = \frac{- 4}{- 2} = 2;\ \ y_{0} = 1\]

\[x\]	\[0\]	\[1\]
\[y\]	\[- 3\]	\[0\]

Ответ: