\[\frac{y + 1}{x - 1} = \frac{5 - 2x}{x - 1}\]
\[\frac{y + 1 - 5 + 2x}{x - 1} = 0\]
\[y - 4 + 2x = 0;\ \ \ x eq 1\]
\[y = 4 - 2x;\ \ \ \ x eq 1\]