\[b_{1} = - \frac{1}{27};\ \ q = - 3:\]
\[b_{8} = b_{1} \cdot q^{7} = - \frac{1}{27} \cdot ( - 3)^{7} =\]
\[= \frac{( - 3)^{7}}{( - 3)^{3}} = 3^{4} = 81.\]