Найдите значение выражения x_0-y_0, если (x_0; y_0) – решение системы уравнений 8(4x-3)-9(2y-3)=13; 0,7x+0,3y=2,3.

\[\left\{ \begin{matrix} 8 \cdot (4x - 3) - 9 \cdot (2y - 3) = 13 \\ 0,7x + 0,3y = 2,3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ | \cdot 10 \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 32x - 24 - 18y + 27 = 13 \\ 7x + 3y = 23\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 32x - 18y = 10\ \ \ \ \ \ \ \\ 7x + 3y = 23\ \ | \cdot 6\ \ \ \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} 32x - 18y = 10\ \ \ \\ 42x + 18y = 138 \\ \end{matrix} \right.\ ( + )\]

\[74x = 148\]

\[x = 148\ :74\]

\[x = 2.\]

\[3y = 23 - 7x = 23 - 7 \cdot 2 = 23 - 14\]

\[3y = 9\]

\[y = 3.\]

\[\left\{ \begin{matrix} x_{0} = 2 \\ y_{0} = 3 \\ \end{matrix} \right.\ \]

\[x_{0} - y_{0} = 2 - 3 = - 1.\]

\[Ответ:3) - 1.\]