\[\frac{x - 6y^{2}}{2y} + 3y^{\backslash 2y} = \frac{x - 6y^{2} + 6y^{2}}{2y} = \frac{x}{2y};\]
\[x = - 8;\ \ y = 0,1:\]
\[\frac{- 8}{2 \cdot 0,1} = - \frac{8}{0,2} = - \frac{80}{2} = - 40.\]