\[\left( \frac{9}{4} \right)^{- 2} \cdot 2^{- 5} = \left( \frac{4}{9} \right)^{2} \cdot \frac{1}{32} =\]
\[= \frac{16 \cdot 1}{81 \cdot 32} = \frac{1}{162}\]