\[x = \frac{1}{3}\]
\[\frac{4x^{2} - 1}{x^{2} + 2x + 1} - \frac{3x^{2}}{x^{2} + 2x + 1} =\]
\[= \frac{4x^{2} - 1 - 3x^{2}}{x^{2} + 2x + 1} =\]
\[= \frac{x^{2} - 1}{x^{2} + 2x + 1} =\]
\[\frac{\frac{1}{3} - 1\ }{\frac{1}{3} + 1\ } = \frac{- \frac{2}{3}}{\frac{4}{3}} = - \frac{2}{3} \cdot \frac{3}{4} = - \frac{1}{2}.\]