Найдите значение выражения (4-7x^2)/(2-x)-(6x^2)/(2-x) при x=-3/4.

\[x = - \frac{3}{4}\]

\[\frac{4 - 7x^{2}}{2 - x} - \frac{6x^{2}}{2 - x} =\]

\[= \frac{4 - 7x^{2} - 6x^{2}}{2 - x} = \frac{4 - 13x²}{2 - x}\]

\[\frac{4 - 13 \cdot \left( - \frac{3}{4} \right)^{2}}{2 - \left( - \frac{3}{4} \right)} = \frac{4 - 13 \cdot \frac{9}{16}}{2 + \frac{3}{4}} =\]

\[= \frac{4 - \frac{117}{16}}{\frac{8 + 3}{4}} = \frac{\frac{64 - 117}{16}}{\frac{11}{4}} =\]

\[= - \frac{53}{16} \cdot \frac{4}{11} = - \frac{53}{44} = - 1\frac{9}{44}.\]