\[\frac{(3x)^{3} \cdot x^{- 9}}{x^{- 10} \cdot 2x^{5}} = \frac{27x^{3} \cdot x^{10}}{x^{9} \cdot 2x^{5}} = \frac{27}{2x};\]
\[x = 5:\]
\[\frac{27}{2x} = \frac{27}{10} = 2,7.\]