\[\left( \frac{3}{4} \right)^{- 2} \cdot 2^{- 3} = \left( \frac{4}{3} \right)^{2} \cdot \left( \frac{1}{2} \right)^{3} =\]
\[= \frac{16}{9} \cdot \frac{1}{8} = \frac{2}{9}\]