\[3^{- 2} + \left( \frac{18}{5} \right)^{- 1} = \frac{1}{3^{2}} + \frac{5}{18} = \frac{1^{\backslash 2}}{9} + \frac{5}{18} =\]
\[= \frac{2 + 5}{18} = \frac{7}{18}\]