\[x = 1\frac{1}{7} = \frac{8}{7};\ \ \ y = - 0,6:\]
\[14xy - 2y + 7x - 1 =\]
\[= 2y(7x - 1) + (7x - 1) =\]
\[= (7x - 1)(2y + 1)\]
\[\left( 7 \cdot \frac{8}{7} - 1 \right)\left( 2 \cdot ( - 0,6) + 1 \right) =\]
\[= (8 - 1)( - 1,2 + 1) = 7 \cdot ( - 0,2) = - 1,4.\]