\[\frac{x^{2} - 8x - 33}{10x + 30} =\]
\[= \frac{(x + 3)(x - 11)}{10 \cdot (x + 3)} = \frac{x - 11}{10}\]
\[x^{2} - 8x - 33 = (x + 3)(x - 11)\]
\[D = 16 + 33 = 49\]
\[x_{1} = 4 + 7 = 11;\ \ \ \]
\[x_{2} = 4 - 7 = - 3.\]
\[x = - 9:\]
\[\frac{x - 11}{10} = \frac{- 9 - 11}{10} = - 2.\]
\[x = 12:\]
\[\frac{x - 11}{10} = \frac{12 - 11}{10} = \frac{1}{10} = 0,1.\]
\[x = 111:\]
\[\frac{x - 11}{10} = \frac{111 - 11}{10} = 10.\]