Найдите шестой член геометрической прогрессии 18; 6; 2; …

\[18;6;2;\ldots\]

\[b_{1} = 18;\ \ b_{2} = 6;\]

\[q = \frac{b_{2}}{b_{1}} = \frac{6}{18} = \frac{1}{3};\]

\[b_{6} = b_{1} \cdot q^{5} = 18 \cdot \left( \frac{1}{3} \right)^{5} =\]

\[= \frac{18}{3^{5}} = \frac{18}{9 \cdot 27} = \frac{2}{27}.\]