Найдите решения уравнения (4x-3)/(3x-4)+(3x-4)/(4x-3)-2=0.

\[\frac{4x - 3^{\backslash 4x - 3}}{3x - 4} + \frac{3x - 4^{\backslash 3x - 4}}{4x - 3} - 2^{\backslash(3x - 4)(4x - 3)} = 0\]

\[16x^{2} - 24x + 9 + 9x^{2} - 24x + 16 -\]

\[- 2\left( 12x^{2} - 16x - 9x + 12 \right) = 0\]

\[25x^{2} - 48x + 25 - 24x^{2} + 50x - 24 = 0\]

\[x^{2} + 2x + 1 = 0\]

\[(x + 1)^{2} = 0\]

\[x + 1 = 0\]

\[x = - 1.\]

\[Ответ:x = - 1.\]