Найдите решение системы уравнений: x-y=1; y-z=2; z-x=-3.

\[\left\{ \begin{matrix} x - y = 1\ \ \ \\ y - z = 2\ \ \ \\ z - x = - 3 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = x - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ z = x - 3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ x - 1 - (x - 3) = 2 \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = x - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ z = x - 3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ x - 1 - x + 3 = 2\ \\ \end{matrix} \right.\ \]

\[\left\{ \begin{matrix} y = x - 1 \\ z = x - 3 \\ 2 = 2\ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \text{\ \ \ \ \ \ \ \ \ }\]

\[\left\{ \begin{matrix} y = x - 1\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ z = x - 3\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ x - любое\ число \\ \end{matrix} \right.\ \]

\[Ответ:(x;x - 1;x - 3).\]