\[y = \sqrt{9 - x²} + \sqrt{5 - 2x}\]
\[1)\ 9 - x^{2} \geq 0\]
\[x^{2} - 9 \leq 0\]
\[(x + 3)(x - 3) \leq 0.\]
\[2)\ 5 - 2x \geq 0\]
\[- 2x \geq - 5\]
\[x \leq 2,5\]
\[Ответ:x \in \lbrack - 3;2,5\rbrack.\]