Найдите корни уравнения: (x-2)(x+2)=7x-14.

\[(x - 2)(x + 2) = 7x - 14\]

\[x^{2} - 4 - 7x + 14 = 0\]

\[x^{2} - 7x + 10 = 0\]

\[D = b^{2} - 4ac =\]

\[= 49 - 4 \cdot 1 \cdot 10 = 49 - 40 = 9\]

\[x_{1} = \frac{7 + 3}{2} = \frac{10}{2} = 5\]

\[x_{2} = \frac{7 - 3}{2} = \frac{4}{2} = 2\]

\[Ответ:x = 5\ \ и\ \ \ x = 2.\]