Найдите корни уравнения: (x^2-3)/2-6x=5.

\[\frac{x^{2} - 3}{2} - 6x = 5\ \ \ \ \ | \cdot 2\]

\[x^{2} - 3 - 12x = 10\]

\[x^{2} - 12x - 13 = 0\]

\[D = b^{2} - 4ac =\]

\[= 144 - 4 \cdot 1 \cdot ( - 13) =\]

\[= 144 + 52 = 196\]

\[x_{1} = \frac{12 + 14}{2} = \frac{26}{2} = 13\]

\[x_{2} = \frac{12 - 14}{2} = - \frac{2}{2} = - 1\]

\[Ответ:x = 13\ \ и\ \ \ x = - 1.\]