Найдите корень уравнения: (x+3)/7=(2x-1)/5.

\[\frac{x + 3}{7} = \frac{2x - 1}{5}\]

\[5 \cdot (x + 3) = 7 \cdot (2x - 1)\]

\[5x + 15 = 14x - 7\]

\[5x - 14x = - 7 - 15\]

\[- 9x = - 22\]

\[x = 22\ :9 = \frac{22}{9}\]

\[x = 2\frac{4}{9}.\]

\[Ответ:x = 2\frac{4}{9}.\]