\[y = x^{2};\ \ \ y = - 2x + 3;\ \]
\[x^{2} = - 2x + 3\]
\[x^{2} + 2x - 3 = 0\]
\[D_{1} = 1 + 3 = 4\]
\[x_{1} = - 1 + 2 = 1;\ \]
\[x_{2} = - 1 - 2 = - 3.\]
\[y_{1} = x^{2} = 1^{2} = 1;\]
\[y_{2} = x^{2} = ( - 3)^{2} = 9.\]
\[Ответ:(1;1);( - 3;9).\]