Найдите: g(-2); g(2); g(0); если g(x)=(x-5)/(x+3).

\[g(x) = \frac{x - 5}{x + 3}\]

\[g( - 2) = \frac{- 2 - 5}{- 2 + 3} = - 7;\]

\[g(2) = \frac{2 - 5}{2 + 3} = - \frac{3}{5} = - 0,6;\]

\[g(0) = \frac{0 - 5}{0 + 3} = - \frac{5}{3} = - 1\frac{2}{3}.\]