Вопрос:

Найди корень уравнения (d-1)/11=(2d-3)/8.

Ответ:

\[\frac{d - 1}{11} = \frac{2d - 3}{8}\]

\[8 \cdot (d - 1) = 11 \cdot (2d - 3)\]

\[8d - 8 = 22d - 33\]

\[22d - 8d = 33 - 8\]

\[14d = 25\]

\[d = 25\ :14\]

\[d = 1\frac{11}{14}.\]


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