\[36x^{2} + \frac{1}{x^{2}} = 13;\]
\[\left( 6x + \frac{1}{x} \right)^{2} = 36x^{2} + 12 + \frac{1}{x^{2}} =\]
\[= 36x^{2} + \frac{1}{x^{2}} + 12 =\]
\[= 13 + 12 = 25;\]
\[6x + \frac{1}{x} = \sqrt{25} = 5.\]
\[Ответ:5.\]