Функция задана формулой у=-1/3*х. Найдите: значение х, при котором у = -1; 2/3; 1/4; 0,2.

\[y = - \frac{1}{3}x\]

\[y = - 1:\]

\[- \frac{1}{3}x = - 1\ \ \]

\[x = 3.\]

\[y = \frac{2}{3}:\ \ \]

\[- \frac{1}{3}x = \frac{2}{3}\text{\ \ }\]

\[x = - 2.\]

\[y = \frac{1}{4}:\ \ \]

\[- \frac{1}{3}x = \frac{1}{4}\text{\ \ }\]

\[x = - \frac{3}{4} = - 0,75.\]

\[y = 0,2:\ \ \]

\[- \frac{1}{3}x = 0,2\ \ \]

\[x = - 0,6.\]