Докажите тождество: (1/(x-7)^2+2/(x^2-49)+1/(x+7)^2)∶(16x^4)/(x^2-49)^2=1/(4x^2).

\[\frac{4x^{2}}{16x^{4}} = \frac{1}{4x^{2}}\]

\[\frac{1}{4x^{2}} = \frac{1}{4x^{2}}.\]