\[\frac{- 5\sin{140{^\circ}} + 4\cos{130{^\circ}}}{\cos{130{^\circ}}} = 1\]
\[\frac{5\sin{40{^\circ}} - 4\sin{40{^\circ}}}{\sin{40{^\circ}}} = 1\]
\[\frac{\sin{40{^\circ}}}{\sin{40{^\circ}}} = 1\]
\[1 = 1.\]