Для каждого значения a решите систему неравенств: x^2+9x+8>=0; x<a.

\[\left\{ \begin{matrix} x² + 9x + 8 \geq 0 \\ x < a\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \\ \end{matrix} \right.\ \]

\[x^{2} + 9x + 8 \geq 0\]

\[x_{1} + x_{2} = - 9,\ \ x_{1} \cdot x_{2} = 8\]

\[x_{1} = - 8,\ \ x_{2} = - 1\]

\[(x + 8)(x + 1) \geq 0\]

\[x \leq - 8;\ \ x \geq - 1.\]

\[при\ \ a \leq - 8 \Longrightarrow ( - \infty;a);\]