Дана функция y=f(x), где f(x)=x^2. При каких значениях аргумента верно равенство f(x-4)=f(x+3)?

\[y = f(x);\ \ \ f(x) = x^{2}\]

\[f(x - 4) = f(x + 3)\]

\[(x - 4)^{2} = (x + 3)^{2}\]

\[(x - 4)^{2} - (x + 3)^{2} = 0\]

\[(x - 4 - x - 3)(x - 4 + x + 3) =\]

\[= 0\]

\[- 7 \bullet (2x - 1) = 0\]

\[2x - 1 = 0\]

\[2x = 1\]

\[x = \frac{1}{2}.\]

\[Ответ:\ \frac{1}{2}.\]