\[x_{1} = 8;\]
\[x^{2} + px - 32 = 0\]
\[\left\{ \begin{matrix} x_{1} + x_{2} = - p \\ x_{1} \cdot x_{2} = - 32 \\ \end{matrix} \right.\ \]
\[8x_{2} = - 32\]
\[x_{2} = - 4.\]
\[8 + ( - 4) = - p\]
\[4 = - p\]
\[p = - 4.\]
\[Ответ:\ \ p = - 4;\ x_{2} = - 4.\]