a) \( \frac{(a - b)^2}{18b} - \frac{(a - b)^2}{12b} + \frac{a^2 - b^2}{36b} = \frac{2(a - b)^2 - 3(a - b)^2 + a^2 - b^2}{36b} = \frac{-(a - b)^2 + a^2 - b^2}{36b} = \frac{a^2 - 2ab + b^2 + a^2 - b^2}{36b} = \frac{2a^2 - 2ab}{36b} = \frac{a(a - b)}{18b} \)