Вычислите: (-1 1/3)^2.

Ответ:

\[\left( - 1\frac{1}{3} \right)^{2} = \left( 1\frac{1}{3} \right)^{2} = \left( \frac{3 + 1}{3} \right)^{2} =\]

\[= \left( \frac{4}{3} \right)^{2} = \frac{4^{2}}{3^{2}} = \frac{16}{9} = 1\frac{7}{9}\]