Сократите дробь: (x^3+64)/(x^2-7xy+4x-28y).

Ответ:

\[\frac{x^{3} + 64}{x^{2} - 7xy + 4x - 28y} =\]

\[= \frac{x^{3} + 64}{x(x - 7y) + 4(x - 7y)} =\]

\[= \frac{(x + 4)\left( x^{2} - 4x + 16 \right)}{(x - 7y)(x + 4)} =\]

\[= \frac{x^{2} - 4x + 16}{x - 7y}.\]