Сократите дробь: (3x^2-4x-4)/(2-x).

Ответ:

\[\frac{3x^{2} - 4x - 4}{2 - x} = \frac{(x - 2)(3x + 1)}{2 - x} =\]

\[= - \frac{(2 - x)(3x + 1)}{2 - x} = - 3x - 1.\]

\[3x^{2} - 4x - 4 =\]

\[= 3(x - 2)\left( x + \frac{1}{3} \right) =\]

\[= (x - 2)(3x + 1)\]

\[D_{1} = 4 + 12 = 16\]

\[x_{1} = \frac{2 + 4}{3} = 2;\]

\[x_{2} = \frac{2 - 4}{3} = - \frac{1}{3}.\]