Решите уравнение: 16+5(-c-2(c-4))=12(3-2c)-1.

Ответ:

\[16 + 5 \cdot \left( - c - 2 \cdot (c - 4) \right) =\]

\[= 12 \cdot (3 - 2c) - 1\]

\[16 - 5c - 10 \cdot (c - 4) =\]

\[= 36 - 24c - 1\]

\[- 5c + 24c - 10c + 40 = 35 - 16\]

\[9c = 19 - 40\]

\[9c = - 21\]

\[c = - \frac{21}{9} = - \frac{7}{3}\]

\[c = - 2\frac{1}{3}.\]