Решите неравенство: (x^2-9)(x^2+2x+1)<0.

Ответ:

\[\left( x^{2} - 9 \right)\left( x^{2} + 2x + 1 \right) < 0\]

\[\left( x^{2} - 9 \right)(x + 1)^{2} < 0\]

\[(x + 1)^{2} \geq 0;\]

\[(x + 3)(x - 3) < 0\]

\[- 3 < x < 3.\]